Есть ли библиотека или класс/функция, которые я могу использовать для преобразования целого в это вербальное представление?
Пример ввода:
4,567,788`
Пример вывода:
Четыре миллиона пятьсот шестьдесят семь тысяч семьсот восемьдесят восемь
Как преобразовать целое число в его словесное представление?
Ответ 1
если вы используете код, найденный в: преобразование чисел в слова С# и вам нужно это для десятичных чисел, вот как это сделать:
public string DecimalToWords(decimal number)
{
if (number == 0)
return "zero";
if (number < 0)
return "minus " + DecimalToWords(Math.Abs(number));
string words = "";
int intPortion = (int)number;
decimal fraction = (number - intPortion)*100;
int decPortion = (int)fraction;
words = NumericToWords(intPortion);
if (decPortion > 0)
{
words += " and ";
words += NumericToWords(decPortion);
}
return words;
}
Ответ 2
В настоящее время лучшая, самая надежная библиотека для этого, безусловно, Humanizer. Он открывается и доступен как nuget:
Console.WriteLine(4567788.ToWords()); // => four million five hundred and sixty-seven thousand seven hundred and eighty-eight
Он также имеет широкий спектр инструментов для решения небольших проблем, которые каждое приложение имеет с string s, enum s, DateTime s, TimeSpan и т.д. и поддерживает множество разных языков.
Console.WriteLine(4567788.ToOrdinalWords().Underscore().Hyphenate().ApplyCase(LetterCasing.AllCaps)); // => FOUR-MILLION-FIVE-HUNDRED-AND-SIXTY-SEVEN-THOUSAND-SEVEN-HUNDRED-AND-EIGHTY-EIGHTH
Ответ 3
Полностью рекурсивная версия:
private static string[] ones = {
"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine",
"ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen",
};
private static string[] tens = { "zero", "ten", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety" };
private static string[] thous = { "hundred", "thousand", "million", "billion", "trillion", "quadrillion" };
public static string ToWords(decimal number)
{
if (number < 0)
return "negative " + ToWords(Math.Abs(number));
int intPortion = (int)number;
int decPortion = (int)((number - intPortion) * (decimal) 100);
return string.Format("{0} dollars and {1} cents", ToWords(intPortion), ToWords(decPortion));
}
private static string ToWords(int number, string appendScale = "")
{
string numString = "";
if (number < 100)
{
if (number < 20)
numString = ones[number];
else
{
numString = tens[number / 10];
if ((number % 10) > 0)
numString += "-" + ones[number % 10];
}
}
else
{
int pow = 0;
string powStr = "";
if (number < 1000) // number is between 100 and 1000
{
pow = 100;
powStr = thous[0];
}
else // find the scale of the number
{
int log = (int)Math.Log(number, 1000);
pow = (int)Math.Pow(1000, log);
powStr = thous[log];
}
numString = string.Format("{0} {1}", ToWords(number / pow, powStr), ToWords(number % pow)).Trim();
}
return string.Format("{0} {1}", numString, appendScale).Trim();
}
Текущее работает до (коротких) квадриллионов. Дополнительную поддержку (для больших чисел или для long scale) можно добавить просто, изменив переменную thous.
Возможно, излишне сложный (специальный случай для сотен ошибок меня немного), учитывая, что изменение нерекурсивной версии также довольно просто.
Ответ 4
Вот испанская версия:
public static string numeroALetras(int number)
{
if (number == 0)
return "cero";
if (number < 0)
return "menos " + numeroALetras(Math.Abs(number));
string words = "";
if ((number / 1000000) > 0)
{
words += numeroALetras(number / 1000000) + " millón ";
number %= 1000000;
}
if ((number / 1000) > 0)
{
words += (number / 1000) == 1? "mil ": numeroALetras(number / 1000) + " mil ";
number %= 1000;
}
if ((number / 100) == 1)
{
if (number == 100)
words += "cien";
else words += (number / 100)> 1? numeroALetras(number / 100) + " ciento ":"ciento ";
number %= 100;
}
if ((number / 100) > 1)
{
var hundredMap = new[] {"","", "dosc", "tresc", "cuatroc", "quin", "seisc", "sietec", "ochoc", "novec" };
if (number > 199)
words += hundredMap[number/100] + "ientos ";
else {
words += numeroALetras(number / 100) + " ientos ";
}
number %= 100;
}
if (number > 0)
{
if (words != "")
words += " ";
var unitsMap = new[] { "cero", "uno", "dos", "tres", "cuatro", "cinco", "seis", "siete", "ocho", "nueve", "diez", "once", "doce", "trece", "catorce", "quince", "dieciseis", "diecisiete", "dieciocho", "diecinueve", "veinte" };
var tensMap = new[] { "cero", "diez", "veinti", "treinta", "cuarenta", "cincuenta", "sesenta", "setenta", "ochenta", "noventa" };
if (number < 21)
words += unitsMap[number];
else
{
words += tensMap[number / 10];
if ((number % 10) > 0)
words += ((number % 10)>2?" y ": "") + unitsMap[number % 10];
}
}
return words;
}
Ответ 5
Imports System.Text
Public Class NumberWriter
Public Shared Function Parse(ByVal Number As String) As String
If Not AreNumbers(Number) Then Return ""
Dim TempQueue As New Queue(Of String)
For Each ItemA As Char In Number.Replace(",", "").Reverse
TempQueue.Enqueue(ItemA)
Next
Dim Blocks As New List(Of String)
Dim BlockEmpty As New List(Of Boolean)
Do
Dim TempBlock As New StringBuilder(3)
TempBlock.Append(TempQueue.Dequeue)
If TempQueue.Count > 0 Then
TempBlock.Append(TempQueue.Dequeue)
If TempQueue.Count > 0 Then
TempBlock.Append(TempQueue.Dequeue)
End If
End If
Blocks.Add(StrReverse(TempBlock.ToString))
BlockEmpty.Add(TempBlock.ToString = "000")
If TempQueue.Count < 1 Then Exit Do
Loop
Dim ResultStack As New Stack(Of String)
For int1 As Integer = 0 To Blocks.Count - 1
ResultStack.Push(ReadBlock(Blocks(int1)) & If(Not int1 = 0, If(Not BlockEmpty(int1), " " & CapitalizeWord(GetPlaceValueSet(int1)) & If(BlockEmpty(int1 - 1), "", ", "), ""), ""))
Next
Dim Result1 As String = ""
Do Until ResultStack.Count < 1
Result1 &= ResultStack.Pop
Loop
Return RemoveGrammarErrors(Result1)
End Function
Private Shared Function RemoveGrammarErrors(ByVal Str As String) As String
Dim tstr As String = Str
tstr.Replace(" ", " ")
tstr.Replace(" , ", ", ")
Return tstr
End Function
Private Shared Function AreNumbers(ByVal Str1 As String) As Boolean
Dim Numbers() As String = {"0", "1", "2", "3", "4", "5", "6", "7", "8", "9", ","}
For Each ItemA As Char In Str1
Dim IsN As Boolean = False
For Each ItemB As String In Numbers
If ItemA = ItemB Then IsN = True
Next
If Not IsN Then
Return False
End If
Next
Return True
End Function
Private Shared Function ReadBlock(ByVal Block As String)
Select Case Block.Length
Case 1
Return ReadSingleDigit(Block)
Case 2
Return ReadTwoDigits(Block)
Case 3
Return ReadThreeDigits(Block)
Case Else
Throw New Exception
End Select
End Function
Private Shared Function ReadThreeDigits(ByVal Digits As String)
If Digits.Length > 3 Then Throw New ArgumentException("There are too many digits.")
Dim Result As String = ""
If Not Digits(0) = "0" Then
Result &= ReadSingleDigit(Digits(0)) & " Hundred "
End If
Result &= ReadTwoDigits(Digits.Substring(1))
Return Result
End Function
Private Shared Function ReadTwoDigits(ByVal Digits As String)
If Digits.Length > 2 Then Throw New ArgumentException("There are too many digits.")
Select Case Digits(0)
Case "0"
Return ReadSingleDigit(Digits(1))
Case "1"
Return ReadTeenNumber(Digits)
Case Else
Return ReadFirstInNumberPair(Digits(0)) & If(Digits(1) = "0", "", "-" & ReadSingleDigit(Digits(1)))
End Select
End Function
Private Shared Function ReadSingleDigit(ByVal Digit As String) As String
If Not Digit.Length = 1 Then Throw New ArgumentException("There must be only one digit and it must be more than zero.")
Select Case Digit
Case "0"
Return ""
Case "1"
Return "One"
Case "2"
Return "Two"
Case "3"
Return "Three"
Case "4"
Return "Four"
Case "5"
Return "Five"
Case "6"
Return "Six"
Case "7"
Return "Seven"
Case "8"
Return "Eight"
Case "9"
Return "Nine"
Case Else
Throw New Exception()
End Select
End Function
Private Shared Function ReadTeenNumber(ByVal Num As String) As String
Select Case Num
Case "11"
Return "Eleven"
Case "12"
Return "Twelve"
Case "13"
Return "Thirteen"
Case "14"
Return "Fourteen"
Case "15"
Return "Fifteen"
Case "16"
Return "Sixteen"
Case "17"
Return "Seventeen"
Case "18"
Return "Eighteen"
Case "19"
Return "Nineteen"
Case Else
Throw New Exception()
End Select
End Function
Private Shared Function ReadFirstInNumberPair(ByVal Num As String) As String
If Not (Num > 1 OrElse Num < 10) Then Throw New ArgumentException("Number must be more than 1 and less than 10")
Select Case Num
Case "2"
Return "Twenty"
Case "3"
Return "Thirty"
Case "4"
Return "Fourty"
Case "5"
Return "Fifty"
Case "6"
Return "Sixty"
Case "7"
Return "Seventy"
Case "8"
Return "Eighty"
Case "9"
Return "Ninety"
Case Else
Throw New Exception()
End Select
End Function
Private Shared Function CapitalizeWord(ByVal Word As String) As String
Return Word.Substring(0, 1).ToUpper & Word.Substring(1)
End Function
Private Shared Function GetPlaceValueSet(ByVal Num As Byte) As String
Select Case Num
Case 0
Return "" 'Hundreds
Case 1
Return "Thousand"
Case 2
Return "Million"
Case 3
Return "Billion"
Case 4
Return "Trillion"
Case 5
Return "Quadrillion"
Case 6
Return "Quintillion"
Case 7
Return "Sextillion"
Case 8
Return "Septillion"
Case 9
Return "Octillion"
Case 10
Return "Nonillion"
Case 11
Return "octillion"
Case 12
Return "nonillion"
Case 13
Return "decillion"
Case 14
Return "undecillion"
Case 15
Return "dodecillion,"
Case 16
Return "tredecillion"
Case 17
Return "quattuordecillion"
Case 18
Return "quindecillion"
Case 19
Return "sexdecillion"
Case 20
Return "septendecillion"
Case 21
Return "octodecillion"
Case 22
Return "novemdecillion"
Case 23
Return "vigintillion"
Case 24
Return "unvigintillion"
Case 25
Return "dovigintillion"
Case 26
Return "trevigintillion"
Case 27
Return "quattuorvigintillion"
Case 28
Return "quinvigintillion"
Case 29
Return "sexvigintillion"
Case 30
Return "septenvigintillion"
Case 31
Return "octovigintillion"
Case 32
Return "novemvigintillion"
Case 33
Return "trigintillion"
Case 34
Return "untrigintillion"
Case 35
Return "dotrigintillion"
Case 36
Return "tretrigintillion"
Case 37
Return "quattuortrigintillion"
Case 38
Return "quintrigintillion"
Case 39
Return "sextrigintillion"
Case 40
Return "septentrigintillion"
Case 41
Return "octotrigintillion"
Case Else
Throw New Exception
End Select
End Function
End Class
Извините, что в VB.NET, но он работает полностью. Это один из способов. Номер для вербального. Я верю, что обрабатывает цифры длиной до 123 символов.
Ответ 6
http://www.exchangecore.com/blog/convert-number-words-c-sharp-console-application/ содержит некоторые С# script, которые обрабатывают очень большие числа и очень маленькие десятичные числа.
using System;
using System.Collections.Generic;
using System.Text;
namespace NumWords
{
class Program
{
// PROGRAM HANDLES NEGATIVE AND POSITIVE DOUBLES
static String NumWordsWrapper(double n)
{
string words = "";
double intPart;
double decPart = 0;
if (n == 0)
return "zero";
try {
string[] splitter = n.ToString().Split('.');
intPart = double.Parse(splitter[0]);
decPart = double.Parse(splitter[1]);
} catch {
intPart = n;
}
words = NumWords(intPart);
if (decPart > 0) {
if (words != "")
words += " and ";
int counter = decPart.ToString().Length;
switch (counter) {
case 1: words += NumWords(decPart) + " tenths"; break;
case 2: words += NumWords(decPart) + " hundredths"; break;
case 3: words += NumWords(decPart) + " thousandths"; break;
case 4: words += NumWords(decPart) + " ten-thousandths"; break;
case 5: words += NumWords(decPart) + " hundred-thousandths"; break;
case 6: words += NumWords(decPart) + " millionths"; break;
case 7: words += NumWords(decPart) + " ten-millionths"; break;
}
}
return words;
}
static String NumWords(double n) //converts double to words
{
string[] numbersArr = new string[] { "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen" };
string[] tensArr = new string[] { "twenty", "thirty", "fourty", "fifty", "sixty", "seventy", "eighty", "ninty" };
string[] suffixesArr = new string[] { "thousand", "million", "billion", "trillion", "quadrillion", "quintillion", "sextillion", "septillion", "octillion", "nonillion", "decillion", "undecillion", "duodecillion", "tredecillion", "Quattuordecillion", "Quindecillion", "Sexdecillion", "Septdecillion", "Octodecillion", "Novemdecillion", "Vigintillion" };
string words = "";
bool tens = false;
if (n < 0) {
words += "negative ";
n *= -1;
}
int power = (suffixesArr.Length + 1) * 3;
while (power > 3) {
double pow = Math.Pow(10, power);
if (n >= pow) {
if (n % pow > 0) {
words += NumWords(Math.Floor(n / pow)) + " " + suffixesArr[(power / 3) - 1] + ", ";
} else if (n % pow == 0) {
words += NumWords(Math.Floor(n / pow)) + " " + suffixesArr[(power / 3) - 1];
}
n %= pow;
}
power -= 3;
}
if (n >= 1000) {
if (n % 1000 > 0) words += NumWords(Math.Floor(n / 1000)) + " thousand, ";
else words += NumWords(Math.Floor(n / 1000)) + " thousand";
n %= 1000;
}
if (0 <= n && n <= 999) {
if ((int)n / 100 > 0) {
words += NumWords(Math.Floor(n / 100)) + " hundred";
n %= 100;
}
if ((int)n / 10 > 1) {
if (words != "")
words += " ";
words += tensArr[(int)n / 10 - 2];
tens = true;
n %= 10;
}
if (n < 20 && n > 0) {
if (words != "" && tens == false)
words += " ";
words += (tens ? "-" + numbersArr[(int)n - 1] : numbersArr[(int)n - 1]);
n -= Math.Floor(n);
}
}
return words;
}
static void Main(string[] args)
{
Console.Write("Enter a number to convert to words: ");
Double n = Double.Parse(Console.ReadLine());
Console.WriteLine("{0}", NumWordsWrapper(n));
}
}
}
РЕДАКТИРОВАТЬ: перевести код из сообщения в блоге
Ответ 7
Вот мое решение, надеюсь, это поможет вам
namespace ConsoleApplication3
{
class Program
{
static void Main(string[] args)
{
string s = Console.ReadLine();
ConvertMyword(int.Parse(s));
Console.Read();
}
static void ConvertMyword(int number)
{
int flag = 0;
int lflag = 0;
string words = String.Empty;
string[] places = { "ones", "ten", "hundred", "thousand", "ten thousand", "lacs","tenlacs","crore","tencrore" };
string rawnumber = number.ToString();
char[] a = rawnumber.ToCharArray();
Array.Reverse(a);
for (int i = a.Length - 1; i >= 0; i--)
{
if (i % 2 == 0 && i > 2)
{
if (int.Parse(a[i].ToString()) > 1)
{
if (int.Parse(a[i - 1].ToString()) == 0)
{
words = words + getNumberStringty(int.Parse(a[i].ToString())) + " " + places[i - 1] + " ";
}
else
{
words = words + getNumberStringty(int.Parse(a[i].ToString())) + " ";
}
}
else if (int.Parse(a[i].ToString()) == 1)
{
if (int.Parse(a[i - 1].ToString())== 0)
{
words = words +"Ten" + " ";
}
else
{
words = words + getNumberStringteen(int.Parse(a[i - 1].ToString())) + " ";
}
flag = 1;
}
}
else
{
if (i == 1 || i == 0)
{
if (int.Parse(a[i].ToString()) > 1)
{
words = words + getNumberStringty(int.Parse(a[i].ToString())) + " " + getNumberString(int.Parse(a[0].ToString())) + " ";
break;
}
else if (int.Parse(a[i].ToString()) == 1)
{
if (int.Parse(a[i - 1].ToString()) == 0)
{
words = words + "Ten" + " ";
}
else
{
words = words + getNumberStringteen(int.Parse(a[i - 1].ToString())) + " ";
}
break;
}
else if (int.Parse(a[i - 1].ToString()) != 0)
{
words = words + getNumberString(int.Parse(a[i - 1].ToString())) + " ";
break;
}
else
{
break;
}
}
else
{
if (flag == 0)
{
for(int l=i;l>=0;l--)
{
if (int.Parse(a[l].ToString())!=0)
{
lflag = 1;
}
}
if (lflag == 1 && int.Parse(a[i].ToString())!=0)
{
words = words + getNumberString(int.Parse(a[i].ToString())) + " " + places[i] + " ";
lflag = 0;
}
else if(lflag == 0)
{
// words = words + getNumberString(int.Parse(a[i].ToString())) + " " + places[i] + " ";
lflag = 0;
break;
}
}
else
{
words = words + " " + places[i] + " ";
flag = 0;
}
}
}
}
Console.WriteLine(words);
}
static string getNumberString(int num)
{
string Word = String.Empty;
switch (num)
{
case 1:
Word = "one";
break;
case 2:
Word = "two";
break;
case 3:
Word = "three";
break;
case 4:
Word = "four";
break;
case 5:
Word = "five";
break;
case 6:
Word = "six";
break;
case 7:
Word = "seven";
break;
case 8:
Word = "eight";
break;
case 9:
Word = "nine";
break;
}
return Word;
}
static string getNumberStringty(int num)
{
string Word = String.Empty;
switch (num)
{
case 2:
Word = "twenty";
break;
case 3:
Word = "thirty";
break;
case 4:
Word = "fourty";
break;
case 5:
Word = "fifty";
break;
case 6:
Word = "sixty";
break;
case 7:
Word = "seventy";
break;
case 8:
Word = "eighty";
break;
case 9:
Word = "ninty";
break;
}
return Word;
}
static string getNumberStringteen(int num)
{
string Word = String.Empty;
switch (num)
{
case 1:
Word = "eleven";
break;
case 2:
Word = "tewlve";
break;
case 3:
Word = "thirteen";
break;
case 4:
Word = "fourteen";
break;
case 5:
Word = "fifteen";
break;
case 6:
Word = "sixteen";
break;
case 7:
Word = "seventeen";
break;
case 8:
Word = "eighteen";
break;
case 9:
Word = "ninteen";
break;
}
return Word;
}
}
}
Ответ 8
Если кто-то хочет версию JavaScript
Number.prototype.numberToWords = function () {
var unitsMap = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"];
var tensMap = ["zero", "ten", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"];
var num = this.valueOf();
if (Math.round(num == 0)) {
return "zero";
}
if (num < 0) {
var positivenum = Math.abs(num);
return "minus " + Number(positivenum).numberToWords();
}
var words = "";
if (Math.floor(num / 1000000) > 0) {
words += Math.floor(num / 1000000).numberToWords() + " million ";
num = Math.floor(num % 1000000);
}
if (Math.floor(num / 1000) > 0) {
words += Math.floor(num / 1000).numberToWords() + " thousand ";
num = Math.floor(num % 1000);
}
if (Math.floor(num / 100) > 0) {
words += Math.floor(num / 100).numberToWords() + " hundred ";
num = Math.floor(num % 100);
}
if (Math.floor(num > 0)) {
if (words != "") {
words += "and ";
}
if (num < 20) {
words += unitsMap[num];
}
else {
words += tensMap[Math.floor(num / 10)];
if ((num % 10) > 0) {
words += "-" + unitsMap[Math.round(num % 10)];
}
}
}
return words.trim();
}
Ответ 9
Мне было поручено создать WEB API, который преобразует числа в слова с помощью С#.
Может быть целым числом или десятичной точкой в течение 48 часов.
Вызов будет поступать из внешнего приложения с использованием метода Ajax Post и вернуть преобразованный результат на веб-страницу.
Я публично передал этот проект в GitHub для ссылки: https://github.com/marvinglennlacuna/NumbersToWordsConverter.Api
Со следующей технической реализацией:
- Структура MVC
- Контроллер API
- Сервис
- Model
- Обработка ошибок
- Тестирование устройств с использованием MSTest
- Покрытие кода - 98%
- Jquery
И с технической документацией о следующем:
- Цель
- Предпосылки
- Требования к функции
- Диаграмма процесса и выход
** Результат через веб-страницу (US-001) **
US-001 Преобразование чисел в слова через процесс веб-страницы
US-001 Преобразование чисел в слова через вывод веб-страницы
Результат через Postman (US-002)
US-002 - Преобразование чисел в слова через процесс почтмана
US-002 - Преобразование чисел в слова через вывод Postman
Я думаю, что просто стоит поделиться рабочим решением в том случае, если вам это нужно для справки в интервью/тестировании кода/школе или только для удовольствия.
Cheers, Марвин
Ответ 10
Этот класс отлично преобразует ваш float или double (до 2 точности). Просто скопируйте и вставьте в свою среду IDE и посмотрите результат.
class ConversionClass
{
private static Dictionary<int, string> InitialNumbers = new Dictionary<int, string>();
private static Dictionary<int, string> MultipleOfTen = new Dictionary<int, string>();
private static Dictionary<int, string> MultipleOfHundered = new Dictionary<int, string>();
private static void InitializeStatic()
{
//InitialNumbers.Add(0, "zero");
InitialNumbers.Add(1, "one");
InitialNumbers.Add(2, "two");
InitialNumbers.Add(3, "three");
InitialNumbers.Add(4, "four");
InitialNumbers.Add(5, "five");
InitialNumbers.Add(6, "six");
InitialNumbers.Add(7, "seven");
InitialNumbers.Add(8, "eight");
InitialNumbers.Add(9, "nine");
InitialNumbers.Add(10, "ten");
InitialNumbers.Add(11, "eleven");
InitialNumbers.Add(12, "tweleve");
InitialNumbers.Add(13, "thirteen");
InitialNumbers.Add(14, "fourteen");
InitialNumbers.Add(15, "fifteen");
InitialNumbers.Add(16, "sixteen");
InitialNumbers.Add(17, "seventeen");
InitialNumbers.Add(18, "eighteen");
InitialNumbers.Add(19, "nineteen");
MultipleOfTen.Add(1, "ten");
MultipleOfTen.Add(2, "twenty");
MultipleOfTen.Add(3, "thirty");
MultipleOfTen.Add(4, "fourty");
MultipleOfTen.Add(5, "fifty");
MultipleOfTen.Add(6, "sixty");
MultipleOfTen.Add(7, "seventy");
MultipleOfTen.Add(8, "eighty");
MultipleOfTen.Add(9, "ninety");
MultipleOfHundered.Add(2, "hundred"); // 100
MultipleOfHundered.Add(3, "thousand"); // 1 000
MultipleOfHundered.Add(4, "thousand"); // 10 000
MultipleOfHundered.Add(5, "thousand"); // 100 000
MultipleOfHundered.Add(6, "million"); // 1 000 000
MultipleOfHundered.Add(7, "million"); // 100 000 000
MultipleOfHundered.Add(8, "million"); // 1 000 000 000
MultipleOfHundered.Add(9, "billion"); // 1 000 000 000 000
}
public static void Main()
{
InitializeStatic();
Console.WriteLine("Enter number :");
var userInput = Console.ReadLine();
double userValue ;
if (double.TryParse(userInput, out userValue)) // userValue = 193524019.50
{
int decimalPortion = (int)userValue;
//var fractionPortion = Math.Ceiling(((userValue < 1.0) ? userValue : (userValue % Math.Floor(userValue))) * 100);
int fractionPortion = (int)(userValue * 100) - ((int)userValue * 100);
int digit; int power;
StringBuilder numberInText = new StringBuilder();
while (decimalPortion > 0)
{
GetDigitAndPower(decimalPortion, out digit, out power);
numberInText.Append(ConvertToText(ref decimalPortion, ref digit, ref power));
if (decimalPortion > 0)
{
decimalPortion = GetReminder(decimalPortion, digit, power);
}
}
numberInText.Append(" point ");
while (fractionPortion > 0)
{
GetDigitAndPower(fractionPortion, out digit, out power);
numberInText.Append(ConvertToText(ref fractionPortion, ref digit, ref power));
if (fractionPortion > 0)
{
fractionPortion = GetReminder(fractionPortion, digit, power);
}
}
Console.WriteLine(numberInText.ToString());
}
Console.ReadKey();
}
private static int GetReminder(int orgValue, int digit, int power)
{
int returningValue = orgValue - (digit * (int)Math.Pow(10, power));
return returningValue;
}
private static void GetDigitAndPower(int originalValue, out int digit, out int power)
{
for (power = 0, digit = 0; power < 10; power++)
{
var divisionFactor = (int)Math.Pow(10, power);
int operationalValue = (originalValue / divisionFactor);
if (operationalValue <= 0)
{
power = power - 1;
digit = (int)(originalValue / Math.Pow(10, power));
break;
}
}
}
private static string ConvertToText(ref int orgValue, ref int digit, ref int power)
{
string numberToText = string.Empty;
if (power < 2)
{
if (InitialNumbers.ContainsKey(orgValue))
{
//This is for number 1 to 19
numberToText = InitialNumbers[orgValue];
orgValue = 0;
}
else if (MultipleOfTen.ContainsKey(digit))
{
//This is for multiple of 10 (20,30,..90)
numberToText = MultipleOfTen[digit];
}
}
else
{
if (power < 4)
{
numberToText = string.Format("{0} {1}", InitialNumbers[digit], MultipleOfHundered[power]);
}
else
{
StringBuilder sb = new StringBuilder();
int multiplicationFactor = power / 3;
int innerOrgValue = (int) (orgValue / Math.Pow(10, (multiplicationFactor * 3)));
digit = innerOrgValue;
var multiple = MultipleOfHundered[power];
power = power - ((int)Math.Ceiling(Math.Log10(innerOrgValue)) - 1);
int innerPower = 0;
int innerDigit = 0;
while (innerOrgValue > 0)
{
GetDigitAndPower(innerOrgValue, out innerDigit, out innerPower);
var text = ConvertToText(ref innerOrgValue, ref innerDigit, ref innerPower);
sb.Append(text);
sb.Append(" ");
if (innerOrgValue > 0)
{
innerOrgValue = GetReminder(innerOrgValue, innerDigit, innerPower);
}
}
sb.Append(multiple);
numberToText = sb.ToString();
}
}
return numberToText + " ";
}
}
Ответ 11
Хотя это старый вопрос, я реализовал эту функциональность с более подробным подходом
public static class NumberToWord
{
private static readonly Dictionary<long, string> MyDictionary = new Dictionary<long, string>();
static NumberToWord()
{
MyDictionary.Add(1000000000000000, "quadrillion");
MyDictionary.Add(1000000000000, "trillion");
MyDictionary.Add(1000000000, "billion");
MyDictionary.Add(1000000, "million");
MyDictionary.Add(1000, "thousand");
MyDictionary.Add(100, "hundread");
MyDictionary.Add(90, "ninety");
MyDictionary.Add(80, "eighty");
MyDictionary.Add(70, "seventy");
MyDictionary.Add(60, "sixty");
MyDictionary.Add(50, "fifty");
MyDictionary.Add(40, "fourty");
MyDictionary.Add(30, "thirty");
MyDictionary.Add(20, "twenty");
MyDictionary.Add(19, "nineteen");
MyDictionary.Add(18, "eighteen");
MyDictionary.Add(17, "seventeen");
MyDictionary.Add(16, "sixteen");
MyDictionary.Add(15, "fifteen");
MyDictionary.Add(14, "fourteen");
MyDictionary.Add(13, "thirteen");
MyDictionary.Add(12, "twelve");
MyDictionary.Add(11, "eleven");
MyDictionary.Add(10, "ten");
MyDictionary.Add(9, "nine");
MyDictionary.Add(8, "eight");
MyDictionary.Add(7, "seven");
MyDictionary.Add(6, "six");
MyDictionary.Add(5, "five");
MyDictionary.Add(4, "four");
MyDictionary.Add(3, "three");
MyDictionary.Add(2, "two");
MyDictionary.Add(1, "one");
MyDictionary.Add(0, "zero");
}
/// <summary>
/// To the verbal.
/// </summary>
/// <param name="value">The value.</param>
/// <returns></returns>
public static string ToVerbal(this int value)
{
return ToVerbal((long) value);
}
/// <summary>
/// To the verbal.
/// </summary>
/// <param name="value">The value.</param>
/// <returns></returns>
public static string ToVerbal(this long value)
{
if (value == 0) return MyDictionary[value];
if (value < 0)
return $" negative {ToVerbal(Math.Abs(value))}";
var builder = new StringBuilder();
for (var i = 1000000000000000; i >= 1000; i = i/1000)
value = ConstructWord(value, builder, i);
value = ConstructWord(value, builder, 100);
for (var i = 90; i >= 20; i = i - 10)
value = ConstructWordForTwoDigit(value, builder, i);
if (MyDictionary.ContainsKey(value))
builder.AppendFormat("{0}" + MyDictionary[value], builder.Length > 0
? " "
: string.Empty);
return builder.ToString();
}
private static long ConstructWord(long value, StringBuilder builder, long key)
{
if (value >= key)
{
var unit = (int) (value/key);
value -= unit*key;
builder.AppendFormat(" {0} {1} " + MyDictionary[key], builder.Length > 0
? ", "
: string.Empty, ToVerbal(unit));
}
return value;
}
private static long ConstructWordForTwoDigit(long value, StringBuilder builder, long key)
{
if (value >= key)
{
value -= key;
builder.AppendFormat(" {0} " + MyDictionary[key], builder.Length > 0
? " "
: string.Empty);
}
return value;
}
}
FYI: у меня есть интерполяция пользовательской строки, которая доступна только в 4.6.1
Ответ 12
Решение, которое занимает меньше кода.
Самая важная часть - только пары строк:
static Func<long, string> remainder = t => t > 0 ? " " + ToEN(t) : "";
public static string ToEN(this long val, double d = 20, long th = 20)
{
switch ((long)d)
{
case 20: return val >= d ? ToEN(val, 1e2) : en[val];
case 100: return val >= d ? ToEN(val, 1e3, 100) : en[val / 10 * 10] + remainder(val % 10);
default: return val >= d ? ToEN(val, d * 1e3,(long)d) : ToEN(val / th) + " " + en[th] + remainder(val % th);
}
}
Полный код доступен здесь https://dotnetfiddle.net/wjr4hF
Ответ 13
Следующий код приложения консоли С# будет принимать денежное значение в количестве до двух десятичных знаков и печатает его на английском языке. Вы можете использовать его в качестве ссылки для достижения ваших результатов.
namespace ConsoleApplication2
{
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
class Program
{
static void Main(string[] args)
{
bool repeat = true;
while (repeat)
{
string inputMonetaryValueInNumberic = string.Empty;
string centPart = string.Empty;
string dollarPart = string.Empty;
Console.Write("\nEnter the monetary value : ");
inputMonetaryValueInNumberic = Console.ReadLine();
inputMonetaryValueInNumberic = inputMonetaryValueInNumberic.TrimStart('0');
if (ValidateInput(inputMonetaryValueInNumberic))
{
if (inputMonetaryValueInNumberic.Contains('.'))
{
centPart = ProcessCents(inputMonetaryValueInNumberic.Substring(inputMonetaryValueInNumberic.IndexOf(".") + 1));
dollarPart = ProcessDollar(inputMonetaryValueInNumberic.Substring(0, inputMonetaryValueInNumberic.IndexOf(".")));
}
else
{
dollarPart = ProcessDollar(inputMonetaryValueInNumberic);
}
centPart = string.IsNullOrWhiteSpace(centPart) ? string.Empty : " and " + centPart;
Console.WriteLine(string.Format("\n\n{0}{1}", dollarPart, centPart));
}
else
{
Console.WriteLine("Invalid Input..");
}
Console.WriteLine("\n\nPress any key to continue or Escape of close : ");
var loop = Console.ReadKey();
repeat = !loop.Key.ToString().Contains("Escape");
Console.Clear();
}
}
private static string ProcessCents(string cents)
{
string english = string.Empty;
string dig3 = Process3Digit(cents);
if (!string.IsNullOrWhiteSpace(dig3))
{
dig3 = string.Format("{0} {1}", dig3, GetSections(0));
}
english = dig3 + english;
return english;
}
private static string ProcessDollar(string dollar)
{
string english = string.Empty;
foreach (var item in Get3DigitList(dollar))
{
string dig3 = Process3Digit(item.Value);
if (!string.IsNullOrWhiteSpace(dig3))
{
dig3 = string.Format("{0} {1}", dig3, GetSections(item.Key));
}
english = dig3 + english;
}
return english;
}
private static string Process3Digit(string digit3)
{
string result = string.Empty;
if (Convert.ToInt32(digit3) != 0)
{
int place = 0;
Stack<string> monetaryValue = new Stack<string>();
for (int i = digit3.Length - 1; i >= 0; i--)
{
place += 1;
string stringValue = string.Empty;
switch (place)
{
case 1:
stringValue = GetOnes(digit3[i].ToString());
break;
case 2:
int tens = Convert.ToInt32(digit3[i]);
if (tens == 1)
{
if (monetaryValue.Count > 0)
{
monetaryValue.Pop();
}
stringValue = GetTens((digit3[i].ToString() + digit3[i + 1].ToString()));
}
else
{
stringValue = GetTens(digit3[i].ToString());
}
break;
case 3:
stringValue = GetOnes(digit3[i].ToString());
if (!string.IsNullOrWhiteSpace(stringValue))
{
string postFixWith = " Hundred";
if (monetaryValue.Count > 0)
{
postFixWith = postFixWith + " And";
}
stringValue += postFixWith;
}
break;
}
if (!string.IsNullOrWhiteSpace(stringValue))
monetaryValue.Push(stringValue);
}
while (monetaryValue.Count > 0)
{
result += " " + monetaryValue.Pop().ToString().Trim();
}
}
return result;
}
private static Dictionary<int, string> Get3DigitList(string monetaryValueInNumberic)
{
Dictionary<int, string> hundredsStack = new Dictionary<int, string>();
int counter = 0;
while (monetaryValueInNumberic.Length >= 3)
{
string digit3 = monetaryValueInNumberic.Substring(monetaryValueInNumberic.Length - 3, 3);
monetaryValueInNumberic = monetaryValueInNumberic.Substring(0, monetaryValueInNumberic.Length - 3);
hundredsStack.Add(++counter, digit3);
}
if (monetaryValueInNumberic.Length != 0)
hundredsStack.Add(++counter, monetaryValueInNumberic);
return hundredsStack;
}
private static string GetTens(string tensPlaceValue)
{
string englishEquvalent = string.Empty;
int value = Convert.ToInt32(tensPlaceValue);
Dictionary<int, string> tens = new Dictionary<int, string>();
tens.Add(2, "Twenty");
tens.Add(3, "Thirty");
tens.Add(4, "Forty");
tens.Add(5, "Fifty");
tens.Add(6, "Sixty");
tens.Add(7, "Seventy");
tens.Add(8, "Eighty");
tens.Add(9, "Ninty");
tens.Add(10, "Ten");
tens.Add(11, "Eleven");
tens.Add(12, "Twelve");
tens.Add(13, "Thrteen");
tens.Add(14, "Fourteen");
tens.Add(15, "Fifteen");
tens.Add(16, "Sixteen");
tens.Add(17, "Seventeen");
tens.Add(18, "Eighteen");
tens.Add(19, "Ninteen");
if (tens.ContainsKey(value))
{
englishEquvalent = tens[value];
}
return englishEquvalent;
}
private static string GetOnes(string onesPlaceValue)
{
int value = Convert.ToInt32(onesPlaceValue);
string englishEquvalent = string.Empty;
Dictionary<int, string> ones = new Dictionary<int, string>();
ones.Add(1, " One");
ones.Add(2, " Two");
ones.Add(3, " Three");
ones.Add(4, " Four");
ones.Add(5, " Five");
ones.Add(6, " Six");
ones.Add(7, " Seven");
ones.Add(8, " Eight");
ones.Add(9, " Nine");
if (ones.ContainsKey(value))
{
englishEquvalent = ones[value];
}
return englishEquvalent;
}
private static string GetSections(int section)
{
string sectionName = string.Empty;
switch (section)
{
case 0:
sectionName = "Cents";
break;
case 1:
sectionName = "Dollars";
break;
case 2:
sectionName = "Thousand";
break;
case 3:
sectionName = "Million";
break;
case 4:
sectionName = "Billion";
break;
case 5:
sectionName = "Trillion";
break;
case 6:
sectionName = "Zillion";
break;
}
return sectionName;
}
private static bool ValidateInput(string input)
{
return Regex.IsMatch(input, "[0-9]{1,18}(\\.[0-9]{1,2})?"))
}
}
}
код >
Ответ 14
Я действительно нуждался в этом для приложения, над которым я работаю, но не был доволен ни одним из решений здесь. FYI, это решение использует поддержку С# 7.0 для локальных функций. Я также использовал новый разделитель цифр, чтобы сделать большие числа более удобочитаемыми.
public static class NumberExtensions
{
private const string negativeWord = "negative";
private static readonly Dictionary<ulong, string> _wordMap = new Dictionary<ulong, string>
{
[1_000_000_000_000_000_000] = "quintillion",
[1_000_000_000_000_000] = "quadrillion",
[1_000_000_000_000] = "trillion",
[1_000_000_000] = "billion",
[1_000_000] = "million",
[1_000] = "thousand",
[100] = "hundred",
[90] = "ninety",
[80] = "eighty",
[70] = "seventy",
[60] = "sixty",
[50] = "fifty",
[40] = "forty",
[30] = "thirty",
[20] = "twenty",
[19] = "nineteen",
[18] = "eighteen",
[17] = "seventeen",
[16] = "sixteen",
[15] = "fifteen",
[14] = "fourteen",
[13] = "thirteen",
[12] = "twelve",
[11] = "eleven",
[10] = "ten",
[9] = "nine",
[8] = "eight",
[7] = "seven",
[6] = "six",
[5] = "five",
[4] = "four",
[3] = "three",
[2] = "two",
[1] = "one",
[0] = "zero"
};
public static string ToWords(this short num)
{
var words = ToWords((ulong)Math.Abs(num));
return num < 0 ? $"{negativeWord} {words}" : words;
}
public static string ToWords(this ushort num)
{
return ToWords((ulong)num);
}
public static string ToWords(this int num)
{
var words = ToWords((ulong)Math.Abs(num));
return num < 0 ? $"{negativeWord} {words}" : words;
}
public static string ToWords(this uint num)
{
return ToWords((ulong)num);
}
public static string ToWords(this long num)
{
var words = ToWords((ulong)Math.Abs(num));
return num < 0 ? $"{negativeWord} {words}" : words;
}
public static string ToWords(this ulong num)
{
var sb = new StringBuilder();
var delimiter = String.Empty;
void AppendWords(ulong dividend)
{
void AppendDelimitedWord(ulong key)
{
sb.Append(delimiter);
sb.Append(_wordMap[key]);
delimiter = 20 <= key && key < 100 ? "-" : " ";
}
if (_wordMap.ContainsKey(dividend))
{
AppendDelimitedWord(dividend);
}
else
{
var divisor = _wordMap.First(m => m.Key <= dividend).Key;
var quotient = dividend / divisor;
var remainder = dividend % divisor;
if (quotient > 0 && divisor >= 100)
{
AppendWords(quotient);
}
AppendDelimitedWord(divisor);
if (remainder > 0)
{
AppendWords(remainder);
}
}
}
AppendWords(num);
return sb.ToString();
}
}
Мясо находится в последней перегрузке ToWords.