Преобразовать координаты в название города?

Ответ 1

SWIFT 2.1: EDIT

MapKit framework обеспечивает способ получения адресных данных из координат.

Вам нужно использовать обратное геокодирование набора карт. Класс CLGeocoder используется для получения местоположения с адреса и адреса из местоположения (координат). Метод reverseGeocodeLocation вернет данные адреса из координат.

Этот метод принимает CLLocation как параметр и возвращает CLPlacemark, который содержит адресный словарь.

Итак, теперь выше метод будет обновлен как:

func didLongPressMap(sender: UILongPressGestureRecognizer) {

    if sender.state == UIGestureRecognizerState.began {
        let touchPoint = sender.location(in: mapView)
        let touchCoordinate = mapView.convert(touchPoint, toCoordinateFrom: self.mapView)
        let annotation = MKPointAnnotation()
        annotation.coordinate = touchCoordinate
        annotation.title = "Your position"
        mapView.addAnnotation(annotation) //drops the pin
        print("lat:  \(touchCoordinate.latitude)")
        let num = touchCoordinate.latitude as NSNumber
        let formatter = NumberFormatter()
        formatter.maximumFractionDigits = 4
        formatter.minimumFractionDigits = 4
        let str = formatter.string(from: num)
        print("long: \(touchCoordinate.longitude)")
        let num1 = touchCoordinate.longitude as NSNumber
        let formatter1 = NumberFormatter()
        formatter1.maximumFractionDigits = 4
        formatter1.minimumFractionDigits = 4
        let str1 = formatter1.string(from: num1)
        adressLoLa.text = "\(num),\(num1)"

        // Add below code to get address for touch coordinates.
        let geoCoder = CLGeocoder()
        let location = CLLocation(latitude: touchCoordinate.latitude, longitude: touchCoordinate.longitude)
        geoCoder.reverseGeocodeLocation(location, completionHandler: { (placemarks, error) -> Void in

            // Place details
            var placeMark: CLPlacemark!
            placeMark = placemarks?[0]

            // Address dictionary
            print(placeMark.addressDictionary as Any)

            // Location name
            if let locationName = placeMark.addressDictionary!["Name"] as? NSString {
                print(locationName)
            }
            // Street address
            if let street = placeMark.addressDictionary!["Thoroughfare"] as? NSString {
                print(street)
            }
            // City
            if let city = placeMark.addressDictionary!["City"] as? NSString {
                print(city)
            }
            // Zip code
            if let zip = placeMark.addressDictionary!["ZIP"] as? NSString {
                print(zip)
            }
            // Country
            if let country = placeMark.addressDictionary!["Country"] as? NSString {
                print(country)
            }
        })
    }
}

Для получения дополнительной информации о адресе изучите класс CLPlacemark. Более подробную информацию вы найдете в разделе addressDictionary.

Ответ 2

Для Swift 3: и Swift 4

Сначала вам нужно установить разрешение на прием GPS-пользователей в info.plist.

Установите: NSLocationWhenInUseUsageDescription со случайной строкой. И/или: NSLocationAlwaysUsageDescription со случайной строкой.

Затем я создал класс для получения желаемых данных, таких как zip, town, country...:

import Foundation
import MapKit

typealias JSONDictionary = [String:Any]

class LocationServices {

    let shared = LocationServices()
    let locManager = CLLocationManager()
    var currentLocation: CLLocation!

    let authStatus = CLLocationManager.authorizationStatus()
    let inUse = CLAuthorizationStatus.authorizedWhenInUse
    let always = CLAuthorizationStatus.authorizedAlways

    func getAdress(completion: @escaping (_ address: JSONDictionary?, _ error: Error?) -> ()) {

        self.locManager.requestWhenInUseAuthorization()

        if self.authStatus == inUse || self.authStatus == always {

            self.currentLocation = locManager.location

            let geoCoder = CLGeocoder()

            geoCoder.reverseGeocodeLocation(self.currentLocation) { placemarks, error in

                if let e = error {

                    completion(nil, e)

                } else {

                    let placeArray = placemarks as? [CLPlacemark]

                    var placeMark: CLPlacemark!

                    placeMark = placeArray?[0]

                    guard let address = placeMark.addressDictionary as? JSONDictionary else {
                        return
                    }

                    completion(address, nil)

                }

            }

        }

    }

}

Вызывается:

import UIKit

class ViewController: UIViewController {

    override func viewDidLoad() {
        super.viewDidLoad()
        LocationServices.shared.getAdress { address, error in

            if let a = address, let city = a["City"] as? String {
               //
            }

        }

    }

}

Готово

Ответ 3

Спасибо @Kampi за это. Это обновленная версия Swift 2.0 (Xcode 7):

func setUsersClosestCity()
{
    let geoCoder = CLGeocoder()
    let location = CLLocation(latitude: _point1.coordinate.latitude, longitude: _point1.coordinate.longitude)
    geoCoder.reverseGeocodeLocation(location)
    {
        (placemarks, error) -> Void in

        let placeArray = placemarks as [CLPlacemark]!

        // Place details
        var placeMark: CLPlacemark!
        placeMark = placeArray?[0]

        // Address dictionary
        print(placeMark.addressDictionary)

        // Location name
        if let locationName = placeMark.addressDictionary?["Name"] as? NSString
        {
            print(locationName)
        }

        // Street address
        if let street = placeMark.addressDictionary?["Thoroughfare"] as? NSString
        {
            print(street)
        }

        // City
        if let city = placeMark.addressDictionary?["City"] as? NSString
        {
            print(city)
        }

        // Zip code
        if let zip = placeMark.addressDictionary?["ZIP"] as? NSString
        {
            print(zip)
        }

        // Country
        if let country = placeMark.addressDictionary?["Country"] as? NSString
        {
            print(country)
        }
    }
}

Ответ 4

Спасибо @Kampai answer, здесь Swift 3 и безопасный (без принуждения !):

let geoCoder = CLGeocoder()
let location = CLLocation(latitude: touchCoordinate.latitude, longitude: touchCoordinate.longitude)

geoCoder.reverseGeocodeLocation(location, completionHandler: { placemarks, error in
    guard let addressDict = placemarks?[0].addressDictionary else {
        return
    }

    // Print each key-value pair in a new row
    addressDict.forEach { print($0) }

    // Print fully formatted address
    if let formattedAddress = addressDict["FormattedAddressLines"] as? [String] {
        print(formattedAddress.joined(separator: ", "))
    }

    // Access each element manually
    if let locationName = addressDict["Name"] as? String {
        print(locationName)
    }
    if let street = addressDict["Thoroughfare"] as? String {
        print(street)
    }
    if let city = addressDict["City"] as? String {
        print(city)
    }
    if let zip = addressDict["ZIP"] as? String {
        print(zip)
    }
    if let country = addressDict["Country"] as? String {
        print(country)
    }
})

Не забывайте NSLocationWhenInUseUsageDescription и NSLocationAlwaysUsageDescription ключи в Swift 3

Ответ 5

Спасибо @Kampai за его ответ, я немного переработал, поэтому он работает с Swift 1.2:

        var geocoder = CLGeocoder()
        var location = CLLocation(latitude: IC.coordinate!.latitude, longitude: IC.coordinate!.longitude)
        geocoder.reverseGeocodeLocation(location) {
            (placemarks, error) -> Void in
            if let placemarks = placemarks as? [CLPlacemark] where placemarks.count > 0 {
                var placemark = placemarks[0]
                println(placemark.addressDictionary)
        }

Результат:

[SubLocality: Sydney, Street: 141 Harrington Street, штат: NSW, SubThoroughfare: 141, CountryCode: AU, ZIP: 2000, Thoroughfare: Harrington Street, Имя: 141 Harrington Street, Страна: Австралия, FormattedAddressLines: (    "141 Харрингтон-стрит",    "Скалы NSW 2000",   Австралия ), Город: Скалы]

Ответ 6

В методе didUpdateToLocation:

- (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:
    (CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation{
    CLLocation *location = [locationManager location];


    CLLocationCoordinate2D coordinate = [location coordinate];


    latitude = [NSString stringWithFormat:@"%.12f", coordinate.latitude];
    longitude = [NSString stringWithFormat:@"%.12f", coordinate.longitude];

    CLLocation *location1 = [[CLLocation alloc]
                             initWithLatitude:latitude.floatValue
                             longitude:longitude.floatValue];

    self.myGeocoder = [[CLGeocoder alloc] init];

    [self.myGeocoder
     reverseGeocodeLocation:location1
     completionHandler:^(NSArray *placemarks, NSError *error) {
        if (error == nil &&
             [placemarks count] > 0){
            placemark = [placemarks lastObject];
            NSString*    vendorLocation=[NSString stringWithFormat:@"%@ %@",
                                          placemark.locality,
                                          placemark.subLocality];
            NSLog(@"%@",vendorLocation);
        }
    }];
}