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Php недели между 2 датами

hi, как не найти недель и каждую дату понедельника между 2 датами. для ex 10-07-2009 по сегодняшний день.

Примечание. Также учитывайте високосный год и другие ограничения, связанные с датой.

4b9b3361

ОТВЕТЫ

Ответ 1

echo datediff('ww', '9 July 2003', '4 March 2004', false);

Найдите функцию на сайте ниже: http://www.addedbytes.com/code/php-datediff-function/

ОБНОВИТЬ

Ссылка теперь не работает (сентябрь 2017 г.), поэтому функция, приведенная ниже, извлечена из веб-архива:

<?php

/**
 * @param $interval
 * @param $datefrom
 * @param $dateto
 * @param bool $using_timestamps
 * @return false|float|int|string
 */
function datediff($interval, $datefrom, $dateto, $using_timestamps = false)
{
    /*
    $interval can be:
    yyyy - Number of full years
    q    - Number of full quarters
    m    - Number of full months
    y    - Difference between day numbers
           (eg 1st Jan 2004 is "1", the first day. 2nd Feb 2003 is "33". The datediff is "-32".)
    d    - Number of full days
    w    - Number of full weekdays
    ww   - Number of full weeks
    h    - Number of full hours
    n    - Number of full minutes
    s    - Number of full seconds (default)
    */

    if (!$using_timestamps) {
        $datefrom = strtotime($datefrom, 0);
        $dateto   = strtotime($dateto, 0);
    }

    $difference        = $dateto - $datefrom; // Difference in seconds
    $months_difference = 0;

    switch ($interval) {
        case 'yyyy': // Number of full years
            $years_difference = floor($difference / 31536000);
            if (mktime(date("H", $datefrom), date("i", $datefrom), date("s", $datefrom), date("n", $datefrom), date("j", $datefrom), date("Y", $datefrom)+$years_difference) > $dateto) {
                $years_difference--;
            }

            if (mktime(date("H", $dateto), date("i", $dateto), date("s", $dateto), date("n", $dateto), date("j", $dateto), date("Y", $dateto)-($years_difference+1)) > $datefrom) {
                $years_difference++;
            }

            $datediff = $years_difference;
        break;

        case "q": // Number of full quarters
            $quarters_difference = floor($difference / 8035200);

            while (mktime(date("H", $datefrom), date("i", $datefrom), date("s", $datefrom), date("n", $datefrom)+($quarters_difference*3), date("j", $dateto), date("Y", $datefrom)) < $dateto) {
                $months_difference++;
            }

            $quarters_difference--;
            $datediff = $quarters_difference;
        break;

        case "m": // Number of full months
            $months_difference = floor($difference / 2678400);

            while (mktime(date("H", $datefrom), date("i", $datefrom), date("s", $datefrom), date("n", $datefrom)+($months_difference), date("j", $dateto), date("Y", $datefrom)) < $dateto) {
                $months_difference++;
            }

            $months_difference--;

            $datediff = $months_difference;
        break;

        case 'y': // Difference between day numbers
            $datediff = date("z", $dateto) - date("z", $datefrom);
        break;

        case "d": // Number of full days
            $datediff = floor($difference / 86400);
        break;

        case "w": // Number of full weekdays
            $days_difference  = floor($difference / 86400);
            $weeks_difference = floor($days_difference / 7); // Complete weeks
            $first_day        = date("w", $datefrom);
            $days_remainder   = floor($days_difference % 7);
            $odd_days         = $first_day + $days_remainder; // Do we have a Saturday or Sunday in the remainder?

            if ($odd_days > 7) { // Sunday
                $days_remainder--;
            }

            if ($odd_days > 6) { // Saturday
                $days_remainder--;
            }

            $datediff = ($weeks_difference * 5) + $days_remainder;
        break;

        case "ww": // Number of full weeks
            $datediff = floor($difference / 604800);
        break;

        case "h": // Number of full hours
            $datediff = floor($difference / 3600);
        break;

        case "n": // Number of full minutes
            $datediff = floor($difference / 60);
        break;

        default: // Number of full seconds (default)
            $datediff = $difference;
        break;
    }

    return $datediff;
}

Ответ 2

Здесь альтернативное решение с использованием DateTime: -

function datediffInWeeks($date1, $date2)
{
    if($date1 > $date2) return datediffInWeeks($date2, $date1);
    $first = DateTime::createFromFormat('m/d/Y', $date1);
    $second = DateTime::createFromFormat('m/d/Y', $date2);
    return floor($first->diff($second)->days/7);
}

var_dump(datediffInWeeks('1/2/2013', '6/4/2013'));// 21

Посмотрите, как работает

Ответ 3

$diff = strtotime($dateto, 0) - strtotime($datefrom, 0);
echo floor($diff / 604800);

Ответ 4

Следующая функция вычисляет "разговорные недели" между двумя временными метками (т.е. на следующей неделе, если вы находитесь в субботу).

function days_between($datefrom,$dateto){
    $fromday_start = mktime(0,0,0,date("m",$datefrom),date("d",$datefrom),date("Y",$datefrom));
    $diff = $dateto - $datefrom;
    $days = intval( $diff / 86400 ); // 86400  / day

    if( ($datefrom - $fromday_start) + ($diff % 86400) > 86400 )
        $days++;

    return  $days;
}

function weeks_between($datefrom, $dateto)
{
    $day_of_week = date("w", $datefrom);
    $fromweek_start = $datefrom - ($day_of_week * 86400) - ($datefrom % 86400);
    $diff_days = days_between($datefrom, $dateto);
    $diff_weeks = intval($diff_days / 7);
    $seconds_left = ($diff_days % 7) * 86400;

    if( ($datefrom - $fromweek_start) + $seconds_left > 604800 )
        $diff_weeks ++;

    return $diff_weeks;
}

Ответ 5

Эта работа отличная

function weeks_between($datefrom, $dateto)
    {
        $datefrom = DateTime::createFromFormat('d/m/Y H:i:s',$datefrom);
        $dateto = DateTime::createFromFormat('d/m/Y H:i:s',$dateto);
        $interval = $datefrom->diff($dateto);
        $week_total = $interval->format('%a')/7;
        return floor($week_total);

    }

weeks_between("25/02/2000 11:30:00","05/06/2015 11:29:59")

Ответ 6

Что-то вроде этого сделало бы работу:

$now = strtotime(date('Y-m-d'));
$end = strtotime(date('2019-06-15'));

$weeksago = date('W', $end) - date('W', $now);

Показывает 9 недель.

Ответ 7

Я обновил Том-код сверху, чтобы функция автоматически определяла строку или int дату/время.

<?php
/**
 * @param $interval
 * @param $datefrom
 * @param $dateto
 * @param bool $using_timestamps // Removed 08-29-2019 Jay Simons - Now auto-detects
 * @return false|float|int|string
 */
function datediff($interval, $datefrom, $dateto)
{
    /*
    $interval can be:
    yyyy - Number of full years
    q    - Number of full quarters
    m    - Number of full months
    y    - Difference between day numbers
           (eg 1st Jan 2004 is "1", the first day. 2nd Feb 2003 is "33". The datediff is "-32".)
    d    - Number of full days
    w    - Number of full weekdays
    ww   - Number of full weeks
    h    - Number of full hours
    n    - Number of full minutes
    s    - Number of full seconds (default)
    */
/*Remove
    if (!$using_timestamps) {
        $datefrom = strtotime($datefrom, 0);
        $dateto   = strtotime($dateto, 0);
    }
*/
    // Auto-detect string date or int date:
    $dateto_str = strtotime($dateto);
    $datefrom_str = strtotime($datefrom);
    if ($dateto_str) $dateto = $dateto_str;
    if ($datefrom_str) $datefrom = $datefrom_str;

    $difference        = $dateto - $datefrom; // Difference in seconds
    $months_difference = 0;

    switch ($interval) {
        case 'yyyy': // Number of full years
            $years_difference = floor($difference / 31536000);
            if (mktime(date("H", $datefrom), date("i", $datefrom), date("s", $datefrom), date("n", $datefrom), date("j", $datefrom), date("Y", $datefrom)+$years_difference) > $dateto) {
                $years_difference--;
            }

            if (mktime(date("H", $dateto), date("i", $dateto), date("s", $dateto), date("n", $dateto), date("j", $dateto), date("Y", $dateto)-($years_difference+1)) > $datefrom) {
                $years_difference++;
            }

            $datediff = $years_difference;
        break;

        case "q": // Number of full quarters
            $quarters_difference = floor($difference / 8035200);

            while (mktime(date("H", $datefrom), date("i", $datefrom), date("s", $datefrom), date("n", $datefrom)+($quarters_difference*3), date("j", $dateto), date("Y", $datefrom)) < $dateto) {
                $months_difference++;
            }

            $quarters_difference--;
            $datediff = $quarters_difference;
        break;

        case "m": // Number of full months
            $months_difference = floor($difference / 2678400);

            while (mktime(date("H", $datefrom), date("i", $datefrom), date("s", $datefrom), date("n", $datefrom)+($months_difference), date("j", $dateto), date("Y", $datefrom)) < $dateto) {
                $months_difference++;
            }

            $months_difference--;

            $datediff = $months_difference;
        break;

        case 'y': // Difference between day numbers
            $datediff = date("z", $dateto) - date("z", $datefrom);
        break;

        case "d": // Number of full days
            $datediff = floor($difference / 86400);
        break;

        case "w": // Number of full weekdays
            $days_difference  = floor($difference / 86400);
            $weeks_difference = floor($days_difference / 7); // Complete weeks
            $first_day        = date("w", $datefrom);
            $days_remainder   = floor($days_difference % 7);
            $odd_days         = $first_day + $days_remainder; // Do we have a Saturday or Sunday in the remainder?

            if ($odd_days > 7) { // Sunday
                $days_remainder--;
            }

            if ($odd_days > 6) { // Saturday
                $days_remainder--;
            }

            $datediff = ($weeks_difference * 5) + $days_remainder;
        break;

        case "ww": // Number of full weeks
            $datediff = floor($difference / 604800);
        break;

        case "h": // Number of full hours
            $datediff = floor($difference / 3600);
        break;

        case "n": // Number of full minutes
            $datediff = floor($difference / 60);
        break;

        default: // Number of full seconds (default)
            $datediff = $difference;
        break;
    }

    return $datediff;
}
?>

Ответ 8

Проверить полный код Нажмите здесь

Все номера недели между двумя датами в PHP

getNoOfWeek() вернет массив недели no. с годом. Вы можете изменить форматирование этого массива из week_text_alter().

function getNoOfWeek($startDate, $endDate){
  // convert date in valid format
  $startDate = date("Y-m-d", strtotime($startDate));
  $endDate = date("Y-m-d", strtotime($endDate));
  $yearEndDay = 31;
  $weekArr = array();
  $startYear = date("Y", strtotime($startDate));
  $endYear = date("Y", strtotime($endDate));

  if($startYear != $endYear) {
    $newStartDate = $startDate;

    for($i = $startYear; $i <= $endYear; $i++) {
      if($endYear == $i) {
        $newEndDate = $endDate;
      } else {
        $newEndDate = $i."-12-".$yearEndDay;
      }
      $startWeek = date("W", strtotime($newStartDate));
      $endWeek = date("W", strtotime($newEndDate));
      if($endWeek == 1){
        $endWeek = date("W", strtotime($i."-12-".($yearEndDay-7)));
      }
      $tempWeekArr = range($startWeek, $endWeek);
      array_walk($tempWeekArr, "week_text_alter", 
         array('pre' => 'Week ', 'post' => " '". substr($i, 2, 2) ));
      $weekArr = array_merge($weekArr, $tempWeekArr);

      $newStartDate = date("Y-m-d", strtotime($newEndDate . "+1 days"));
    }
  } else {
    $startWeek = date("W", strtotime($startDate));
    $endWeek = date("W", strtotime($endDate));
    $endWeekMonth = date("m", strtotime($endDate));
    if($endWeek == 1 && $endWeekMonth == 12){
      $endWeek = date("W", strtotime($endYear."-12-".($yearEndDay-7)));
    }
    $weekArr = range($startWeek, $endWeek);
    array_walk($weekArr, "week_text_alter", 
       array('pre' => 'Week ', 'post' => " '". substr($startYear, 2, 2)));
  }
  $weekArr = array_fill_keys($weekArr, 0);
  return $weekArr;
}

function week_text_alter(&$item1, $key, $prefix)
{
  $item1 = $prefix['pre']. $item1 . $prefix['post'];
}


Output 1 -
$weekArr = getNoOfWeek('2014-01-01', '2014-02-10');

Array
(
    [Week 1 '14] => 0
    [Week 2 '14] => 0
    [Week 3 '14] => 0
    [Week 4 '14] => 0
    [Week 5 '14] => 0
    [Week 6 '14] => 0
    [Week 7 '14] => 0
)

Output 2 -
$weekArr = getNoOfWeek('2013-12-01', '2014-02-10');

Array
(
    [Week 48 '13] => 0
    [Week 49 '13] => 0
    [Week 50 '13] => 0
    [Week 51 '13] => 0
    [Week 52 '13] => 0
    [Week 1 '14] => 0
    [Week 2 '14] => 0
    [Week 3 '14] => 0
    [Week 4 '14] => 0
    [Week 5 '14] => 0
    [Week 6 '14] => 0
    [Week 7 '14] => 0
)

Надеюсь, это поможет вам.

Ответ 9

PHP число недель между двумя датами выпуска

Ниже приведено решение (исправленное решение для одного вопроса, заданного в сообщении - https://stackoverflow.com/info/27560850/php-number-of-week-between-2-dates-issue), чтобы узнать количество недель между диапазоном дат.

Поскольку в приведенном ниже решении используется разность дат, для включения начальной даты в неделю нужно использовать функцию пола, а для включения даты окончания дня необходимо использовать ceil, тогда только она возвращает правильное количество недель

$strtDate = '2014-01-01';
$endDate = '2015-03-17';

$startDateWeekCnt = round(floor( date('d',strtotime($strtDate)) / 7)) ;
// echo $startDateWeekCnt ."\n";
$endDateWeekCnt = round(ceil( date('d',strtotime($endDate)) / 7)) ;
//echo $endDateWeekCnt. "\n";

$datediff = strtotime(date('Y-m',strtotime($endDate))."-01") - strtotime(date('Y-m',strtotime($strtDate))."-01");
$totalnoOfWeek = round(floor($datediff/(60*60*24)) / 7) + $endDateWeekCnt - $startDateWeekCnt ;
echo $totalnoOfWeek ."\n";