Получить URI изображения, хранящегося в чертеже

Ответ 1

Вы должны использовать ContentResolver для открытия URI ресурса:

Uri uri = Uri.parse("android.resource://your.package.here/drawable/image_name");
InputStream stream = getContentResolver().openInputStream(uri);

Также вы можете открыть URI файлов и содержимого, используя этот метод.

Ответ 2

/**
 * get uri to drawable or any other resource type if u wish 
 * @param context - context
 * @param drawableId - drawable res id
 * @return - uri 
 */
public static final Uri getUriToDrawable(@NonNull Context context, 
                                         @AnyRes int drawableId) {
    Uri imageUri = Uri.parse(ContentResolver.SCHEME_ANDROID_RESOURCE +
            "://" + context.getResources().getResourcePackageName(drawableId)
            + '/' + context.getResources().getResourceTypeName(drawableId)
            + '/' + context.getResources().getResourceEntryName(drawableId) );
    return imageUri;
}

на основе выше - подправленная версия для любого ресурса:

 /**
 * get uri to any resource type
 * @param context - context
 * @param resId - resource id
 * @throws Resources.NotFoundException if the given ID does not exist.
 * @return - Uri to resource by given id 
 */
public static final Uri getUriToResource(@NonNull Context context, 
                                         @AnyRes int resId)
                           throws Resources.NotFoundException {
    /** Return a Resources instance for your application package. */
    Resources res = context.getResources();
    /**
     * Creates a Uri which parses the given encoded URI string.
     * @param uriString an RFC 2396-compliant, encoded URI
     * @throws NullPointerException if uriString is null
     * @return Uri for this given uri string
     */
    Uri resUri = Uri.parse(ContentResolver.SCHEME_ANDROID_RESOURCE +
            "://" + res.getResourcePackageName(resId)
            + '/' + res.getResourceTypeName(resId)
            + '/' + res.getResourceEntryName(resId));
    /** return uri */
    return resUri;
}

немного информации:

From the Java Language spec.:

"17.5 Final Field Semantics

... when the object is seen by another thread, that thread will always
see the correctly constructed version of that object final fields.
It will also see versions of any object or array referenced by
those final fields that are at least as up-to-date as the final fields
are."

In that same vein, all non-transient fields within Uri
implementations should be final and immutable so as to ensure true
immutability for clients even when they don't use proper concurrency
control.

For reference, from RFC 2396:

"4.3. Parsing a URI Reference

   A URI reference is typically parsed according to the four main
   components and fragment identifier in order to determine what
   components are present and whether the reference is relative or
   absolute.  The individual components are then parsed for their
   subparts and, if not opaque, to verify their validity.

   Although the BNF defines what is allowed in each component, it is
   ambiguous in terms of differentiating between an authority component
   and a path component that begins with two slash characters.  The
   greedy algorithm is used for disambiguation: the left-most matching
   rule soaks up as much of the URI reference string as it is capable of
   matching.  In other words, the authority component wins."

...

3. URI Syntactic Components

   The URI syntax is dependent upon the scheme.  
   In general, absolute URI are written as follows:

     <scheme>:<scheme-specific-part>

   An absolute URI contains the name of the scheme being used (<scheme>)
   followed by a colon (":") and then a string  (the <scheme-specific-part>) 
   whose interpretation depends on the scheme.

   The URI syntax does not require that the scheme-specific-part have any
   general structure or set of semantics which is common among all URI.
   However, a subset of URI do share a common syntax for representing
   hierarchical relationships within the namespace.  This "generic URI"
   syntax consists of a sequence of four main components:

     <scheme>://<authority><path>?<query>

источники:

• http://www.rfc-base.org/rfc-2396.html

СПОР

этот ответ верен, однако часть о последних полях - нет - это не имеет никакого отношения к ответу - Борис Треухов

@BorisTreukhov - пожалуйста, уточните нам, что вы подразумеваете под "часть о конечных полях неверна" - вопрос - как добраться до...? создать способ, которым он может быть проанализирован (как анализируется URI? см. ответ)

package android.net;

/**
 * Immutable URI reference. A URI reference includes a URI and a fragment, the
 * component of the URI following a '#'. Builds and parses URI references
 * which conform to
 * <a href="http://www.faqs.org/rfcs/rfc2396.html">RFC 2396</a>.
 *
 * <p>In the interest of performance, this class performs little to no
 * validation. Behavior is undefined for invalid input. This class is very
 * forgiving--in the face of invalid input, it will return garbage
 * rather than throw an exception unless otherwise specified.
 */
 public abstract class Uri implements Parcelable, Comparable<Uri> { ... }

Ответ 3

Это то, что вам действительно нужно:

 Uri imageUri = Uri.parse(ContentResolver.SCHEME_ANDROID_RESOURCE +
 "://" + getResources().getResourcePackageName(R.drawable.ic_launcher)
 + '/' + getResources().getResourceTypeName(R.drawable.ic_launcher) + '/' + getResources().getResourceEntryName(R.drawable.ic_launcher) );

Ответ 4

Вы можете использовать Uri.Builder вместо конкатенации строк

 Uri imageUri = (new Uri.Builder())
    .scheme(ContentResolver.SCHEME_ANDROID_RESOURCE)
    .authority(resources.getResourcePackageName(resourceId))
    .appendPath(resources.getResourceTypeName(resourceId))
    .appendPath(resources.getResourceEntryName(resourceId))
    .build()

Ответ 5

Самый простой ответ будет: Uri.parse (Строка идет сюда); // Итак, чтобы сделать растягиваемый элемент внутри этой скобки, вам просто нужно сделать это.

Uri.parse(getResource().getDrawable(R.drawable.ic_launcher_background).toString());

Это.

Ответ 6

Для Котлина

context.resources.getResourcePackageName(R.drawable.image_name)