Сводная таблица SQL Server с несколькими агрегатами столбцов

Ответ 1

Я бы сделал это несколько иначе, применив как функции UNPIVOT, так и PIVOT, чтобы получить окончательный результат. Неповтор принимает значения из столбцов totalcount и totalamount и помещает их в один столбец с несколькими строками. Затем вы можете опираться на эти результаты.:

select chardate,
  Australia_totalcount as [Australia # of Transactions], 
  Australia_totalamount as [Australia Total $ Amount],
  Austria_totalcount as [Austria # of Transactions], 
  Austria_totalamount as [Austria Total $ Amount]
from
(
  select 
    numericmonth, 
    chardate,
    country +'_'+col col, 
    value
  from
  (
    select numericmonth, 
      country, 
      chardate,
      cast(totalcount as numeric(10, 2)) totalcount,
      cast(totalamount as numeric(10, 2)) totalamount
    from mytransactions
  ) src
  unpivot
  (
    value
    for col in (totalcount, totalamount)
  ) unpiv
) s
pivot
(
  sum(value)
  for col in (Australia_totalcount, Australia_totalamount,
              Austria_totalcount, Austria_totalamount)
) piv
order by numericmonth

Смотрите SQL Fiddle with Demo.

Если у вас есть неизвестное количество имен country, вы можете использовать динамический SQL:

DECLARE @cols AS NVARCHAR(MAX),
    @colsName AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX)

select @cols = STUFF((SELECT distinct ',' + QUOTENAME(country +'_'+c.col) 
                      from mytransactions
                      cross apply 
                      (
                        select 'TotalCount' col
                        union all
                        select 'TotalAmount'
                      ) c
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

select @colsName 
    = STUFF((SELECT distinct ', ' + QUOTENAME(country +'_'+c.col) 
               +' as ['
               + country + case when c.col = 'TotalCount' then ' # of Transactions]' else 'Total $ Amount]' end
             from mytransactions
             cross apply 
             (
                select 'TotalCount' col
                union all
                select 'TotalAmount'
             ) c
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

set @query 
  = 'SELECT chardate, ' + @colsName + ' 
     from 
     (
      select 
        numericmonth, 
        chardate,
        country +''_''+col col, 
        value
      from
      (
        select numericmonth, 
          country, 
          chardate,
          cast(totalcount as numeric(10, 2)) totalcount,
          cast(totalamount as numeric(10, 2)) totalamount
        from mytransactions
      ) src
      unpivot
      (
        value
        for col in (totalcount, totalamount)
      ) unpiv
     ) s
     pivot 
     (
       sum(value)
       for col in (' + @cols + ')
     ) p 
     order by numericmonth'

execute(@query)

Смотрите скрипт SQL с демонстрацией

Оба дают результат:

|             CHARDATE | AUSTRALIA # OF TRANSACTIONS | AUSTRALIA TOTAL $ AMOUNT | AUSTRIA # OF TRANSACTIONS | AUSTRIA TOTAL $ AMOUNT |
--------------------------------------------------------------------------------------------------------------------------------------
| Jul-12               |                          36 |                   699.96 |                        11 |                 257.82 |
| Aug-12               |                          44 |                  1368.71 |                         5 |                 126.55 |
| Sep-12               |                          52 |                  1161.33 |                         7 |                  92.11 |
| Oct-12               |                          50 |                  1099.84 |                        12 |                 103.56 |
| Nov-12               |                          38 |                  1078.94 |                        21 |                 377.68 |
| Dec-12               |                          63 |                  1668.23 |                         3 |                  14.35 |

Ответ 2

Я добавил динамический запрос/решение.

Static

SELECT  t.chardate,
        SUM(CASE WHEN t.country='Australia' THEN t.totalcount ELSE 0 END) AS "Australia # of Transactions",
        SUM(CASE WHEN t.country='Australia' THEN t.totalamount ELSE 0 END) AS "Australia Total $ amount",
        SUM(CASE WHEN t.country='Austria' THEN t.totalcount ELSE 0 END) AS "Austria # of Transactions",
        SUM(CASE WHEN t.country='Austria' THEN t.totalamount ELSE 0 END) AS "Austria Total $ amount"
FROM    mytransactions t
GROUP BY t.chardate;

Примечание:

1) ORDER BY t.chardate не будет работать, потому что значения из столбца chardate равны char s.

2) Мой совет состоит в разделении chardate в двух столбцах numericmonth и numericyear. В этом последнем случае вы можете использовать это решение:

SELECT  t.numericyear, t.numericmonth,
        SUM(CASE WHEN t.country='Australia' THEN t.totalcount ELSE 0 END) AS "Australia # of Transactions",
        SUM(CASE WHEN t.country='Australia' THEN t.totalamount ELSE 0 END) AS "Australia Total $ amount",
        SUM(CASE WHEN t.country='Austria' THEN t.totalcount ELSE 0 END) AS "Austria # of Transactions",
        SUM(CASE WHEN t.country='Austria' THEN t.totalamount ELSE 0 END) AS "Austria Total $ amount"
FROM    mytransactions t
GROUP BY t.numericyear, t.numericmonth
ORDER BY BY t.numericyear, t.numericmonth;

Динамический

DECLARE @Sql NVARCHAR(MAX)='SELECT t.chardate';
DECLARE @ColumnTemplate NVARCHAR(MAX)='SUM(CASE WHEN t.country=''{country}'' THEN t.totalcount ELSE 0 END) AS "{country} # of Transactions"
,SUM(CASE WHEN t.country=''{country}'' THEN t.totalamount ELSE 0 END) AS "{country} Total $ amount"'

SELECT @[email protected]+CHAR(13)+','+REPLACE(@ColumnTemplate, '{country}', REPLACE(c.name,'''','''''')e)
FROM (
    SELECT  DISTINCT t.country AS name
    FROM    mytransactions t
) c

SELECT @[email protected]+'
FROM mytransactions t
GROUP BY t.chardate;'

PRINT @Sql;


EXEC(@Sql);

Результаты:

SELECT t.chardate
,SUM(CASE WHEN t.country='Australia' THEN t.totalcount ELSE 0 END) AS "Australia # of Transactions"
,SUM(CASE WHEN t.country='Australia' THEN t.totalamount ELSE 0 END) AS "Australia Total $ amount"
,SUM(CASE WHEN t.country='Austria' THEN t.totalcount ELSE 0 END) AS "Austria # of Transactions"
,SUM(CASE WHEN t.country='Austria' THEN t.totalamount ELSE 0 END) AS "Austria Total $ amount"
FROM mytransactions t
GROUP BY t.chardate;

Примечание. Функция REPLACE из SELECT @[email protected]+CHAR(13)+ ... REPLACE(c.name,'''','''''')) используется для предотвращения SQL injections.

Ответ 3

Я использовал свой собственный свод как вложенный запрос и пришел к такому результату:

SELECT
  [sub].[chardate],
  SUM(ISNULL([Australia], 0)) AS [Transactions Australia],
  SUM(CASE WHEN [Australia] IS NOT NULL THEN [TotalAmount] ELSE 0 END) AS [Amount Australia],
  SUM(ISNULL([Austria], 0)) AS [Transactions Austria],
  SUM(CASE WHEN [Austria] IS NOT NULL THEN [TotalAmount] ELSE 0 END) AS [Amount Austria]
FROM
(
  select * 
  from  mytransactions
  pivot (sum (totalcount) for country in ([Australia], [Austria])) as pvt
) AS [sub]
GROUP BY
  [sub].[chardate],
  [sub].[numericmonth]
ORDER BY 
  [sub].[numericmonth] ASC

Вот сценарий.

Ответ 4

Самый сложный, самый простой способ сделать это - просто обернуть свой основной запрос с помощью сводной таблицы в общем выражении таблицы, а затем группировать/агрегировать.

WITH PivotCTE AS
(
    select * from  mytransactions
    pivot (sum (totalcount) for country in ([Australia], [Austria])) as pvt
)
SELECT
    numericmonth,
    chardate,
    SUM(totalamount) AS totalamount,
    SUM(ISNULL(Australia, 0)) AS Australia,
    SUM(ISNULL(Austria, 0)) Austria
FROM PivotCTE
GROUP BY numericmonth, chardate

ISNULL означает остановить значение NULL от сбрасывания суммы (потому что NULL + любое value = NULL)