У меня есть класс Employee
, который определяется как это:
Employee
{
public int Id { get; set; }
public string Name { get; set; }
public DateTime WorkDate { get; set; }
public bool isOff { get; set; }
}
Это реализация и использование моего класса:
List<Employee> workers = new List<Employee>()
{
new Employee { Id = 1, Name = "Emp 1", WorkDate = Convert.ToDateTime("4/11/2016"), IsOff = false},
new Employee { Id = 1, Name = "Emp 1", WorkDate = Convert.ToDateTime("4/12/2016"), IsOff = false},
new Employee { Id = 1, Name = "Emp 1", WorkDate = Convert.ToDateTime("4/13/2016"), IsOff = true},
new Employee { Id = 1, Name = "Emp 1", WorkDate = Convert.ToDateTime("4/14/2016"), IsOff = false},
new Employee { Id = 1, Name = "Emp 1", WorkDate = Convert.ToDateTime("4/15/2016"), IsOff = false},
new Employee { Id = 1, Name = "Emp 1", WorkDate = Convert.ToDateTime("4/16/2016"), IsOff = false},
new Employee { Id = 1, Name = "Emp 1", WorkDate = Convert.ToDateTime("4/17/2016"), IsOff = false},
new Employee { Id = 2, Name = "Emp 2", WorkDate = Convert.ToDateTime("4/11/2016"), IsOff = false},
new Employee { Id = 2, Name = "Emp 2", WorkDate = Convert.ToDateTime("4/12/2016"), IsOff = false},
new Employee { Id = 2, Name = "Emp 2", WorkDate = Convert.ToDateTime("4/13/2016"), IsOff = false},
new Employee { Id = 2, Name = "Emp 2", WorkDate = Convert.ToDateTime("4/14/2016"), IsOff = false},
new Employee { Id = 2, Name = "Emp 2", WorkDate = Convert.ToDateTime("4/15/2016"), IsOff = false},
new Employee { Id = 2, Name = "Emp 2", WorkDate = Convert.ToDateTime("4/16/2016"), IsOff = false},
new Employee { Id = 2, Name = "Emp 2", WorkDate = Convert.ToDateTime("4/17/2016"), IsOff = false},
};
В инициализации выше есть только 1 запись, которая выключена:
Id = 1, Name = "Emp 1" and the WorkDate = 4/13/2016
Теперь, как я могу получить идентификатор сотрудника, который не имеет выходного дня в течение недели (с 11 по 17 апреля)? Это Id = 2
A LINQ
решение намного лучше, но я не знаю, как это сделать.
ОБНОВЛЕНО
Чтобы избежать путаницы объекта Employee
, я изменил его на EmployeeSchedule
class EmployeeSchedule
{
public int Id { get; set; }
public string Name { get; set; }
public DateTime WorkDate { get; set; }
public bool isOff { get; set; }
}
Это реализация
List<EmployeeSchedule> workers = new List<EmployeeSchedule>()
{
new EmployeeSchedule{ Id = 1, Name = "Emp 1", WorkDate = Convert.ToDateTime("4/11/2016"), IsOff = false},
new EmployeeSchedule{ Id = 1, Name = "Emp 1", WorkDate = Convert.ToDateTime("4/12/2016"), IsOff = false},
new EmployeeSchedule{ Id = 1, Name = "Emp 1", WorkDate = Convert.ToDateTime("4/13/2016"), IsOff = true},
new EmployeeSchedule{ Id = 1, Name = "Emp 1", WorkDate = Convert.ToDateTime("4/14/2016"), IsOff = false},
new EmployeeSchedule{ Id = 1, Name = "Emp 1", WorkDate = Convert.ToDateTime("4/15/2016"), IsOff = false},
new EmployeeSchedule{ Id = 1, Name = "Emp 1", WorkDate = Convert.ToDateTime("4/16/2016"), IsOff = false},
new EmployeeSchedule{ Id = 1, Name = "Emp 1", WorkDate = Convert.ToDateTime("4/17/2016"), IsOff = false},
new EmployeeSchedule{ Id = 2, Name = "Emp 2", WorkDate = Convert.ToDateTime("4/11/2016"), IsOff = false},
new EmployeeSchedule{ Id = 2, Name = "Emp 2", WorkDate = Convert.ToDateTime("4/12/2016"), IsOff = false},
new EmployeeSchedule{ Id = 2, Name = "Emp 2", WorkDate = Convert.ToDateTime("4/13/2016"), IsOff = false},
new EmployeeSchedule{ Id = 2, Name = "Emp 2", WorkDate = Convert.ToDateTime("4/14/2016"), IsOff = false},
new EmployeeSchedule{ Id = 2, Name = "Emp 2", WorkDate = Convert.ToDateTime("4/15/2016"), IsOff = false},
new EmployeeSchedule{ Id = 2, Name = "Emp 2", WorkDate = Convert.ToDateTime("4/16/2016"), IsOff = false},
new EmployeeSchedule{ Id = 2, Name = "Emp 2", WorkDate = Convert.ToDateTime("4/17/2016"), IsOff = false},
};
Выбранный ответ по-прежнему применим.