Переименование нескольких файлов в Python

Ответ 1

import os
import glob
files = glob.glob('year*.jpg')
for file in files:
    os.rename(file, 'year_{}'.format(file.split('_')[1]))

Одна строка может быть разбита на:

for file in files:
    parts = file.split('_') #[abc, 2000.jpg]
    new_name = 'year_{}'.format(parts[1]) #year_2000.jpg
    os.rename(file, new_name)

Ответ 2

Потому что сегодня я сделал что-то похожее:

#!/usr/bin/env python

import os
import sys
import re

if __name__ == "__main__":
    _, indir = sys.argv

    infiles = [f for f in os.listdir(indir) if os.path.isfile(os.path.join(indir, f))]

    for infile in infiles:
        outfile = re.sub(r'abc', r'year' , infile)
        os.rename(os.path.join(indir, infile), os.path.join(indir, outfile))

Ответ 3

Вот мое решение, которое написано с комментариями для каждого шага, так что даже новичок может понять и использовать, взломать и настроить:

https://github.com/JerusalemProgramming/PythonAutomatedRenamingOfFilenames/blob/master/program_FileRenameJPEGS.py

## THIS PYTHON FILE NEEDS TO BE RUN WITHIN THE IMAGES FOLDER WITH JPG/JPEG IMAGES WHOSE
## ..FILENAMES NEED RENAMED TO NUMERICAL SEQUENCE (1.jpg, 2.jpg, 3.jpg, 4.jpg... etc.)

## IMPORT MODULES
## IMPORT MODULES
## IMPORT MODULES

import re, glob, os, pathlib

## BEGIN DEFINE FUNCTIONS
## BEGIN DEFINE FUNCTIONS
## BEGIN DEFINE FUNCTIONS

def fn_RenameFiles(files, pattern, replacement):

    ## DECLARE VARIABLES
    ## SET COUNTER FOR LATER USE
    i = 1

    ## BEGIN FOR LOOP
    ## BEGIN FOR LOOP
    ## BEGIN FOR LOOP

    ## FOR EACH PATHNAME IN 
    for pathname in glob.glob(files):

        ## PATHNAME
        #print("pathname =", pathname) ## TEST OUTPUT

        ## BASENAME
        basename = os.path.basename(pathname)
        #print("basename =", basename) ## TEST OUTPUT

        ## IF PATHNAME EQUALS BASENAME...
        if pathname == basename:

            ##...THEN TEST OUTPUT - THIS SHOULD ALWAYS PRINT TRUE
            print("pathname == basename:  TRUE")
            print("pathname string =", pathname) ## STRING FILENAME IN DIRECTORY
            print("basename string =", basename) ## STRING FILENAME IN DIRECTORY

        ## ELSE IF PATHNAME DOES NOT EQUAL BASENAME...
        else:

            ##...THEN TEST OUTPUT
            print("pathname == basename:  FALSE")
            print("pathname string =", pathname) ## STRING FILENAME IN DIRECTORY
            print("basename string =", basename) ## STRING FILENAME IN DIRECTORY

        ## CALCULATE NEW FILENAME WITH REGULAR EXPRESSIONS   
        NewFilename = re.sub(pattern, replacement, basename)

        ## TEST OUTPUT
        print("NewFilename =", NewFilename)


        ## IF NEWFILENAME DOES NOT EQUAL BASENAME...
        if NewFilename != basename:

            ##...THEN RENAME THE PATHNAME WITH NEWFILENAME
            os.rename(pathname, os.path.join(os.path.dirname(pathname), NewFilename))

        ## ELSE DOES THIS CONDTION EVER GET TRIGGERED?
        else:
            print("DOES THIS CONDITION EVER GET TRIGGERED?")


    ## END FOR LOOP
    ## END FOR LOOP
    ## END FOR LOOP

    ## TEST OUTPUT - LIST OF FILENAMES IN DIRECTORY
    print("glob.glob(files) =", glob.glob(files))


    ## BEGIN FOR LOOP
    ## BEGIN FOR LOOP
    ## BEGIN FOR LOOP

    ## FOR EACH FILE IN glob.glob(files)
    for each in glob.glob(files):

    ## FILE PATH TO DIRECTORY OF IMAGES
        ## FILE PATH OF CURRENT WORKING DIRECTORY WITH IMAGES = e.g. C:\RootFolder\images
        filepath = os.path.abspath('') ## = os.getcwd()

        ## TEST OUTPUT - FILE PATH OF CURRENT WORKING DIRECTORY
        print("FILE PATH OF CURRENT WORKING DIRECTORY =", filepath)

        ## RENAME FILES IN CWD; JOIN EMPTY STRING FILEPATH + STRING OF INTEGER OF CURRENT COUNTER + STRING OF .JPG 
        os.rename(os.path.join(filepath, each), os.path.join(filepath, str(i)+'.jpg'))

        ## INCREASE COUNTER
        i = i+1

    ## END FOR LOOP
    ## END FOR LOOP
    ## END FOR LOOP

    ## TEST OUTPUT - LIST OF FILENAMES IN DIRECTORY
    print("glob.glob(files) =", glob.glob(files))

    ## TEST OUTPUT - GAME OVER
    print("GAME OVER.  GO CHECK YOUR IMAGE FOLDER")


## END DEFINE FUNCTIONS
## END DEFINE FUNCTIONS
## END DEFINE FUNCTIONS

### BEGIN MAIN PROGRAM
### BEGIN MAIN PROGRAM
### BEGIN MAIN PROGRAM


## CALL FUNCTION        
fn_RenameFiles("*.jpg", r"^(.*)\.jpg$", r"new(\1).jpg")

### END MAIN PROGRAM
### END MAIN PROGRAM
### END MAIN PROGRAM

## GAME OVER

## WE HOPE YOU ENJOYED AND THAT THIS HELPS YOUR UNDERSTANDING OF USING PYTHON LANGUAGE TO SOLVE PROBLEMS WITH PYTHON PROGRAMMING
## PLEASE COME BACK AGAIN SOON
## PLEASE VISIT OUR WEB SITES (OUR PROBLEM-SOLVING PROGRAMMING, CODING, & DEVELOPMENT SERVICES ARE AVAILABLE FOR HIRE):
## www.JerusalemProgrammer.com
## www.JerusalemProgrammers.com
## www.JerusalemProgramming.com

Ответ 4

# Изменяя одну строку в коде, я думаю, что эта строка будет работать или, возможно, не меняя ничего, что будет работать

import glob2
import os


def rename(f_path, new_name):
    filelist = glob2.glob(f_path + "*.ma")
    count = 0
    for file in filelist:
        print("File Count : ", count)
        filename = os.path.split(file)
        print(filename)
        new_filename = f_path + new_name + str(count + 1) + ".ma"
        os.rename(f_path+filename[1], new_filename)
        print(new_filename)
        count = count + 1

Вызовите функцию, передав два аргумента f_path в качестве вашего пути и new_name, которые вы хотите передать в файл.

Ответ 5

Это позволяет переименовать файл с указанием даты создания.

import os, datetime, time

folder = r"*:\***\***\TEST"

for file in os.listdir(folder):
    date = os.path.getmtime(os.path.join(folder, file))
    new_filename = datetime.datetime.fromtimestamp(date).strftime("%Y%m%d_%H%M%S.%f")[:-4]
    os.rename(os.path.join(folder, file), os.path.join(folder, new_filename + ".pdf"))
    print("Renamed " + file + " to " + new_filename)
    time.sleep(0.1)